OpenExcel(String,Int32,String) Method

In This Topic

Opens an Excel file and loads the specified Excel sheet (by name) into the specified sheet of the Spread component (by index).

Syntax

Visual Basic
C#

'Declaration
 
Public Overloads Function OpenExcel( _
   ByVal fileName As String, _
   ByVal spreadSheetIndex As Integer, _
   ByVal excelSheetName As String _
) As Boolean

'Usage
 
Dim instance As FpSpread
Dim fileName As String
Dim spreadSheetIndex As Integer
Dim excelSheetName As String
Dim value As Boolean
 
value = instance.OpenExcel(fileName, spreadSheetIndex, excelSheetName)

public bool OpenExcel( 
   string fileName,
   int spreadSheetIndex,
   string excelSheetName
)

Parameters

fileName: Path and name of the file to open
spreadSheetIndex: Index of the sheet in the Spread component into which to load the Excel sheet
excelSheetName: Name of the Excel sheet to load

Return Value

Boolean: true if successful; false otherwise

Example

This example opens a Microsoft Excel file, test.xls.

C#
Visual Basic

FpSpread1.OpenExcel("test.xls",0,"Sheet2");

FpSpread1.OpenExcel("test.xls",0,"Sheet2")

Parameters

Return Value

Reference

User-Task Documentation

External