IsShapeInView Method

In This Topic

Determines if a shape is currently within the view determined by the row and column parameters.

Syntax

Visual Basic
C#

'Declaration
 
Public Overridable Function IsShapeInView( _
   ByVal shape As PSShape, _
   ByVal topRow As Integer, _
   ByVal leftColumn As Integer, _
   ByVal bottomRow As Integer, _
   ByVal rightColumn As Integer _
) As Boolean

'Usage
 
Dim instance As SpreadShapesContainer
Dim shape As PSShape
Dim topRow As Integer
Dim leftColumn As Integer
Dim bottomRow As Integer
Dim rightColumn As Integer
Dim value As Boolean
 
value = instance.IsShapeInView(shape, topRow, leftColumn, bottomRow, rightColumn)

public virtual bool IsShapeInView( 
   PSShape shape,
   int topRow,
   int leftColumn,
   int bottomRow,
   int rightColumn
)

Parameters

shape: Shape to check for in view
topRow: Top row of view
leftColumn: Left column of view
bottomRow: Bottom row of view
rightColumn: Right column of view

Return Value

Returns true if shape is in view; otherwise false

Reference

SpreadShapesContainer Class
SpreadShapesContainer Members