Spread.NET 17 Formula Reference
Formula Functions / Functions H to L / HOUR
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    This function returns the hour that corresponds to a specified time.




    Specify the time argument as a number (as in 37806.5) a string (as in "7/4/2003 12:00"), a DateTime object, as in DATE(2003,7,4), or a TimeSpan object, as in TIME(12,0,0). For more details on the date and time inputs, refer to the discussion in Date and Time Functions

    Dates as numeric values are in the form x.y, where x is the "number of days since December 30, 1899" and y is the fraction of day. Numbers to the left represent the date. Times as numeric values are decimal fractions ranging from 0 to 0.99999999, representing the times from 0:00:00 (12:00:00 A.M.) to 23:59:59 (11:59:59 P.M.).


    The hour is returned as an integer, ranging from 0 (12:00 A.M.) to 23 (11:00 P.M.).

    Data Types

    Accepts numeric, string, DateTime object, or TimeSpan object data. Returns numeric data.




    HOUR(0.25) gives the result 6

    HOUR(347.25) gives the result 6

    HOUR("2:22 PM") gives the result 14

    HOUR("2:22 AM") gives the result 2


    Version Available

    This function is available in product version 1.0 or later.

    See Also

    MINUTE | SECOND | Date and Time Functions