Spread Windows Forms 13.0 Product Documentation
FarPoint.Win.Spread Assembly / FarPoint.Win.Spread.Model Namespace / DefaultSheetDataModel Class / CanSerializeXml Property
Example


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    CanSerializeXml Property (DefaultSheetDataModel)
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    Gets whether the object in its entirety can be rendered with XML without losing any information.
    Syntax
    'Declaration
     
    Public ReadOnly Property CanSerializeXml As Boolean
    'Usage
     
    Dim instance As DefaultSheetDataModel
    Dim value As Boolean
     
    value = instance.CanSerializeXml
    public bool CanSerializeXml {get;}

    Property Value

    Boolean: true if every contained object supports XML serialization; false otherwise
    Remarks
    This method returns true if the object can be rendered with XML in its entirety (using the Serialize method) without losing any information. This includes the data, any tags, or data source in the model associated with the object. Some objects can contain custom object references, such as a custom data type, that may or may not implement the XML serialization interface (ISerializeSupport). This method returns false if any of the contained objects do not implement the XML serialization interface.
    Example
    Dim dt As New DataTable("Testing")
    dt.Columns.Add("Number")
    dt.Columns.Add("Letter")
    dt.Rows.Add(New Object() {"1", "One"})
    dt.Rows.Add(New Object() {"2", "Two"})
    Dim dataModel As New FarPoint.Win.Spread.Model.DefaultSheetDataModel(dt)
    FpSpread1.ActiveSheet.Models.Data = dataModel
    dataModel.SetModelDataColumn(0, "Letter")
    dataModel.SetModelDataColumn(1, "Number")
    Dim b As Boolean
    b = dataModel.CanSerializeXml
    ListBox1.Items.Add(b.ToString())
    DataTable dt = new DataTable("Testing");
    dt.Columns.Add("Number");
    dt.Columns.Add("Letter");
    dt.Rows.Add(new Object[]{"1", "One"});
    dt.Rows.Add(new Object[] {"2", "Two"});
    FarPoint.Win.Spread.Model.DefaultSheetDataModel dataModel = new FarPoint.Win.Spread.Model.DefaultSheetDataModel(dt);
    fpSpread1.ActiveSheet.Models.Data = dataModel;
    dataModel.SetModelDataColumn(0, "Letter");
    dataModel.SetModelDataColumn(1, "Number");
    bool b;
    b = dataModel.CanSerializeXml;
    listBox1.Items.Add(b.ToString());
    See Also